Cost Price-
The price at which an article is purchased is called its cost price (C.P.)
Selling
Price- The price at which the
article is sold is called its selling price (S.P.)
SP = Selling Price = The
price at which the object is Sold.
When SP < CP → Loss = CP - SP
When SP > CP → Profit = SP - CP
Note: Loss% and Profit% both are
calculated upon CP
Profit% = [Profit/CP] * 100
Loss% = [Loss/CP] * 100
- Suppose Company A
produces 1000 T.V in Year 2000 And 1200 T.V in Year 2001. On the other
hand Company B produces 5000 T.V in year 2000 and 5500 T.V in year 2001.
Which company has the better growth rate ?
Now Look at company A, The
increase is of 200 T.V and Company B the increase if of 500 T.V So in Numerical
Sense Company B has Produced more than A.
But we are not talking here
about Numerical Growth We are talking about relative Growth. i.e Growth with
respect to it's previous year production. [ Like things are compared with like
thing Only, Just Like you can't compare Apple and Oranges]
Taking That Point Into
Consideration The Growth of Company A with respect to it's Previous year
production will be (200/1000)*100 = 20%
And that for company B it
will be (500/5000)*100 = 10%
So clearly Company A has a
better growth rate than company B.
Cost Price aka CP
In my methods I Consider CP
to be an Absolute Value of 100%. So if anybody Says he made profit of 20% it
means He sells the Object at 120% or C.P 100% and Profit is 20% then it means
SP = 1.2x( It will be more clear to you when i will explain Different Case)
Profit or Loss both are
calculated with respect to C.P i.e CP is Always used as a base while
calculating profit and loss.
Selling Price aka SP
I think by Common Sense you
all know that If SP>CP then you will have profit whose value will be (SP -
CP) In terms Of numerical Value.
And Profit % will be
[(SP-CP)/CP] * 100 or [(Profit/CP)*100] [ remember i told you that profit and
loss both are calculated on CP i.e taking CP as Base, So all you have to do is
calculate Profit in terms of numerical value( SP - CP) and then divide it by
the base(CP) and then multiply it by 100 and you will get your profit %]
Eg. CP of a pen is 10 Rs and SP
is 12 Rs. What is profit and profit % ?
Pretty easy Huh !! Just
calculate profit first So it will be SP - CP = 12-10 = 2RS
And profit %
[(SP-CP)/CP]*100 = [(12-10)/10]*100 = [(2/10)*100] = 20%
So now I think The
difference between profit and profit % is clear to you.
Now If you know What is
Profit then you all must know That what is Loss and when loss Occurs.
Loss occurs when we make
some pretty bad decisions and We go out Nuts and Start selling The object at a
rate less than the purchasing price of the object.
Lets Put that in
Mathematical Way. If CP>SP then there is a case of loss. to Find out
the amount of loss all you have to do is (CP - SP)
And to calculate Loss%
nothing difficult just the usual stuff [(CP-SP)/CP*100] or [(Loss)/CP*100] [
Look again I told you both Loss and profit are calculated taking CP as Base. So
what i have done in the formula is That i calculated Numerical Loss and then
divided it by our BASE i.e CP and Then Multiplies it by 100 To get our Loss%]
And i don't think I have to
explain again the difference between loss and Loss %.
So now Moving On to Other
basic Stuff.
Marked Price aka MP= The
Price at which a Product is Marked[ Like when you go to Your Local Market for
buying Some nice Sunglasses( I mean fake RAY BAN's ;) ) And the Dealer say the
cost is 1000rs and It's Also Marked on the Box but as we all know that it's
just a MARKED PRICE and he will eventually sell that Ray Ban to you at 200Rs,
And well if you are good at Bargaining then he will even sell it you at 100RS,
And If It's me He will give it ME for free and even pay me 50RS back :P Well
just Joking :P So that is our Marked Price]
Discount % = It's like
concession on the MARKED PRICE. The dealer says I Am just giving You a
discount Man You are a regular customer and blah blah blah And you are like my
relative and all the BS( But here is the catch The Discount % is always calculated
on M.P In the above example of RAY BAN if you want to calculate the Discount %
then It's Easy The MP was 1000Rs he Finally Sells you that Ray Ban at 200 So
discount Given = MP - SP i.e 1000-200 = 800rs
Now Discount % is calculated
taking MP as BASE so Discount % will be
[(MP-SP)/MP]*100 =
[(1000-200)/1000]*100 = 80%]
Discount is calculated on MP
but Marking of MP is done with respect to CP.
For example if I say I
bought Something for 500rs and I marked the Product 60% above the CP then It
means I marked the product 60% of 500 = 300 above CP means 500+300 = 800rs.
OK
CASE 1- Simple Profit and
Profit % Calculation
Mohit Purchased A watch for
1000rs and then Sold it to Nimesh for 1250rs. Calculate the Profit and
Profit %?
Most Simple Question Which
You will never get in Any Exam :P( But Basics are Basics we gotta revise it at
least)
So What happens here Mohit
purchases a Watch( You see word Purchase And You know it's CP) at
1000rs
SO C.P = 1000rs
And then he sells it at
1250Rs( You See the Word SELL Ok that's our SP )
So SP = 1250Rs
Now Profit as I told is
nothing but SP - CP So profit = 1250-1000 = 250rs
Now Profit % =
[(Profit)/CP*100] So profit % = [(250/1000)*100] = 25%
CASE - 2
Now The Watch That Nimesh
purchased for 1250rs Is Sold Again by Her at Rs 625. So what will be Loss and
Loss %
Again Usual Stuff
Loss = CP - SP
Loss = 1250 -625 = 625
Loss% = [(loss/CP)*100] =
[(625/125)*100] = 50%
So we have a 50% loss here.
Case 3 Inversion case
Profit or loss% is Give and
CP or SP is Given and you have to find SP or CP
Steve Sells an article for
1200Rs And he makes a profit of 20% in the Transaction. So What is the Cost
price?
I told You once If you don't
Know about Something Then assume it as x.
So we take CP = x
Now If i sell an article at
20% profit then what will be our SP in terms of x ?
yeah it's pretty simple 1.2x
[ Because is told you percentage to decimal conersion So 20% here is nothing
but 0.2x and total SP will be x+ 0.2x = 1.2x remember add in case of profit and
subtract in case of loss]
And according to the
Question he sold the article at 1200rs
So 1.2x = 1200rs
So x = 1000Rs.
Steve again sells an
article for 1200rs but this time he suffers a loss of 20%. What will be the
C.P?
Now just Take CP = x
So as i Told S.P will be ?
yeah 0.8x ( As i said add in case of profit and subtact in case of loss)
and acoording to the
question SP = 1200rs
So 0.8x = 1200
x = 1200/0.8 = 1500rs
So C.P is 1500rs.
If it's given that C.P is
1000rs and profit made is 20%
Then it will be much more
simple.
C.P is 1000rs so profit 20%
will be 200rs.
So Profit = sp-cp therefore
SP = CP + profit = 1000+200=1200rs.
Or If S.P is Given and Also
Discount % is given you have to calculate MP
Example S.P = 200rs
Discount % = 80%
Find MP.
Simple Let M.P be X
So S.P after 80% discount
will be 0.2x
and according to question
S.P = 200
So 0.2x= 200
x = 1000rs = MP
Case 4: Combination Where MP
CP SP are Mixed Together.
An article was purchased for
Rs. 78,350. Its price was marked up by 30%. It was sold at a discount of 20% on
the marked up price. What was the profit percent on the cost price?
Cost price = Rs. 78350
Marked price = 1.3*78350
= 101855( I told in the Start CP is Absolute 100% so If anything is
Marked or Sold Above CP by ---% You just have to add that % to 100% and Convert
it into it's relative decimal value)
Selling price = 101855*0.8=
81484[ Discount is calculated on MP so here MP is Absolute 100%, 20% discount
that Means The product is being Sold at 80% of MP or 0.8MP)
Profit = S.P - CP = 81484 -
78350 = 3134
Profit% = (Profit/CP)*100 =
(3134/78350)*100 = 4%
Case 5
A man purchases 11 oranges
for 10rs and Sells 10 oranges for 11rs.Find profit or loss%?
1st- Basic method.
Find the C.P of 1 orange
that will be 10/11
Find SP of 1 orange that
will be 11/10
As it's clear SP>CP hence
Profit will be SP-CP = 11/10 - 10/11 = (121 - 100)/110 = 21/110
Profit % = [(profit)/CP]*100
= [(21/110)/(10/11)*100] = [(21*11)/(110*10)*100 = 21%
2nd- LCM method.
Take The LCM The two numbers
present in the Question i.e LCM of 10 and 11 = 110.
Now this Is the Amount Of
oranges you will buy and sell and calculate the profit % on that.
So CP of 110 Oranges = 100rs
S.P of 110 Oranges = 121rs
Profit = 21Rs
Profit % = 21%[ calculates
on the CP of 110 Oranges]
3rd - fastest Method but
Confusing
Write The Purchase line
First --- 11 oranges for 10
-------------------------------------------------cross
multiply-----
Selling Line 2nd
10 oranges for 11
11*11 will be SP and 10*10
will Be CP
Profit % = (11*11 -
10*10)/(10*10)*100 = 21%
Lets See one More Example
A man buys 8 pens for rs 9
and sells 9 pens for rs 8, Find profit or loss%?
By LCM method
take lcm of 8 and 9 that
will be 72
CP of 72 pens will be 81rs
SP of 72 Pens will be 64Rs
Clearly there is loss which
will be equal to 81 - 64 = 17rs
Loss % = (17/81)*100 = 20.98
or 21%
BY Fastest Method.
Write the purchase line 8
pen for 9rs
---------------------------------cross
multiply
write sale line
9 pen for 8rs
C.P will be 8*8 = 64
S.P will be 9*9 = 81
Loss% will be (17/81)*100 =
20.98%
Case 6:- Dishonest dealer
using false Weight and selling at Cost price.
A Dishonest dealer Professes
to Sell the product at cost price but Instead of Selling 1000gm He sells only
900gm for 1Kg Wt
You don't need any Formula
to Solve This Type of Question. You just have to use your own Mind here.
Now Look what the dealer is
actually Doing here.
Dealer says He sell at Cost
price Means He say He Sells at the price he purchases.
Now What amount He says He
Sells = 1000gm
What Actually He Sells =
900gm
Now you can See here he is
only selling 900gm and he is getting the oney for 1000gm
So this money from 100 Grams
is His Profit OK.
Now how we calculate profit
% ? We take CP as Base and Divide the Profit by CP.
Now look in this Question he
is Selling 900 Gram and getting 100gram As profit.
So profit % will be
(100/900)*100 = 11.11%
One More Question :
A dishonest dealer Professes
to sell the goods at cost price but instead of selling 1000 gms he sells only
800 gms for 1KG WT. Find his Gain% ?
Now Just Remember what He
says He is Selling or what he gets paid for, he says he sell 1000gram
But What Actually He sells ?
yeah exactly 800grams.
So how much he gets Extra or
how much he cheats = 200grams
So profit will be
(200/800)*100 = 25%
Case 7: Dishonest Dealer and
also Selling Above Cost price.
A dishonest dealer Sells his
Good 20% above the cost Price and Also cheats the Customer By giving them only
800gm for 1kg wt. What's his Profit % in the whole transaction.
We have to do the same stuff
here Just Imagine. If he sells 1kg then how much will get paid for but also
remember that he sells his good above 20% of CP Which means that if he sells
1000gm he gets paid for 1200gm. [ 20% above CP ka matlab yahi hua na ?]
So he gets paid for 1200gms
and What he actually Sells here is ? Yes 800gms Only
So Profit will be SP - CP =
1200 - 800 = 400gm
Profit % will be
(Profit)/CP*100 = [400/800]*100 = 50%
Case 8: When two Articles
are Sold at Same Price but one at profit and one at loss and % profit = %
loss. In Such Cases there will always be a loss (%)which will be equal to
[(Common Gain or Loss)]/10]^2
Example - A man Sell two
Wrist Watches One at a profit of 20% and one at loss of 20%. The selling price
of each watch is 200rs.
i) Find the Percentage of
profit or loss.
ii) Net Amount of profit or
loss.
i) As i told there will
always be a loss in this case And % loss = [(common gain or loss)/100]^100
Now just put the value %
loss = [(20/10)]^2 = 4%
Hence Loss % = 4%
ii) Net Amount of Loss
So His Total SP was 200 +
200 = 400rs
He Suffers a loss = 4% Which
means he sells his watch at 96% of their value i.e CP
So acording to Question 96%
of CP = 400rs
or 0.96CP = 400rs
CP = 400/0.96
CP = 416.6667
So Net Amount of Loss = CP -
SP = 416.667 - 400 = 16.667Rs
Case 9 - Goods passing
through Successive hands.
It's a Lot like the method i
told you yesterday about consecutive increase or decrease.
But Let's just Check it
again.
A sells a good a profit of
20% to B and B Sells That Good to C at a profit of 25% If C pays 225 For It.
What was it's Cpst Price for A.
So Just Asumme that CP for A
was x
So he sells it at 20% profit
That means he sells it at 1.2x
Now S.P of A = C.P of B
So Now B sells it to C at
25% profit
That means B sells it at
1.2*1.25*x
Now C pays 225rs
That mean 1.2*1.25*x = 225
so x = 150Rs
Answer CP for A = 150Rs.
Or you can Also use the
formula which i told yesterday [x + y + (xy)/100]
Same way you can solve for 3
persons also.
Case 10 - CP of X articles =
SP of Y Articles.
Very Simple If you know the
trick behind it.
Eg - CP of 25 Articles is
Equal to the SP of 20 Articles. Find the Profit or loss %.
Just write it This was 25CP
= 20SP
Now Cross multiply So that
Variables gets on One side of the equation and Constant gets on the Other Side.
So SP/CP = 25/20
Now you just have to take
that Elements on the opposite sides of Equation represents their corresponding
value.
So in Equation SP/CP =
25/20. In front of SP the value is 25( So our SP will be 25)
And in front of CP the value
is 20( So out CP is 20)
Now You know CP and SP
calculating profit or loss is a child's play now but still we have to play it[
Personal Advice Always Believe in complete solution of the question, never
leave the question in Mid Way ]
So as SP>CP there is
profit
And profit will be
[(SP-CP)/CP]*100 = (5/20)*100 = 25%
Another Example
CP of 10 articles is equal
to the SP of 12 Articles Find the profit or Loss %?
Do the same stuff again
10CP=12SP
Cross multiply now.
SP/CP = 10/12
So SP = 10
and CP = 12
So clearly there is a loss
And loss % = (Loss/CP)*100 = (2/12)*100 = 16.66%
Case 1: Marking Above x% and
giving discount of y%, Total profit or loss.
Eg A person Marks his good
above 50% of CP and Gives Discount of 20% Find his Profit %.
The easiest way to solve
this type of question is to assume the CP as 100
So CP is 100
M.P will be 50% above CP
that will be 150
Now he gives discount of 20%
As discount is caculated on
MP so SP after deducting the discount will be 150*0.8 = 120
Now SP = 120, CP = 100 So
profit % will be 20%.
Case 12 - Decrease in Price
of Commodity allows A person to Buy X quantity more of an item.
EG - When the price of sugar
decreases by 10%, a man could buy 1 kg more for Rs 270. Then, the
original price and final
price of the sugar are ?
Now remember i told you a
formula yesterday Which Goes something like this[ (How Much It is decreased)/(
What It Becomes after decrease)*100].
So this Question is
Implementation of that Formula only.
Price is decreased by 10%.
So Man can purchase how much
extra now ? Apply the formula ( How much decrease/ What It becomes )*100 =
(10/90)*100 = 100/9 %
So man can buy 100/9 % more
sugar now.
Lets Assume that originally
He used to buy x kg of sugar
And as it's given in the
question He can Buy 1 KG more. So that means that 100/9 % of x = 1kg
(100/900)*x = 1
x = 9kg.
Now Original Quantity = 9kg
So Original Cost = 270/9 =
30Rs/KG
Increased Quantity = 9+1 =
10kg
So Final Price = 270/10 =
27RS/kg
Case 13
A trader allows a discount
of 25% on his articles but wants to gain 50% gain. How many times the CP should
be marked on the items?
Simple way to solve this
Question is By Assuming MP as X and CP as Y.
So Let MP be X, So SP
after 25% discount = 0.75x
And He also Wants to Again
50% on CP, So SP in Terms of y will be = 1.5y
Now Both SP are Equal
So
0.75x = 1.5y[ Now we have to
find MP with respect to CP So express the equation in terms of Y]
x = 2y
or x = 200% of Y
So he Should marks his Goods
100% above the CP.
Case 14:- Successive
Discount.
We all used to get Amazed
when we heard deals like 50% + 49% discount, I always used to wonder how can
they sell their product at 1% price LOL. Then i studied % in class 7th and it
became clear to me that's it's another way of looting commom man.
So what actually is
Successive Discount.
Successive simply means
anything which is applied in succession
So When Pantaloons Say 50% +
30% off It doesn't mean you will get the discount of 80%. If they wanted to
give you 80% discount( which they would never do) then they would simply have
written 80% instead of 50% + 30%.
For Example You wen to
Pantaloons or levis whatever And You Like a jeans Whose MP is 1000rs, and there
is a discount of 50% + 30%. So Now You have to apply the 50% discount, By
applying that New MP will become 500rs and Now On this 500Rs you will apply the
next 30% discount to get the final SP which will be 350Rs.
So Lets See some Examples.
There are 2 Successive
discount on Watch Whose MP is 2000rs. the first Discount is of 40% and other is
of 20%.
The Good thing with
successive discount is that you can apply The discount in any way you want,
that means you can apply 20% discount first and if you want you can apply 40%
discount first. The answer will remain the same.
So now Lets Apply 40%
discount on 2000rs. After applying 40% discount the MP will become 1200rs and
On that 1200 we apply another 20% discount So the final SP will become 960Rs.
Now Do the Other Way. First
Apply 20% discount on 2000rs So new MP will be 1600 Rs Now apply 40% discount
again. And the Final SP will be 960 Rs
You can see the answer is
same in both the cases.
But I will tell you simple
method Just Multiply It.
I means MP is 2000 You want
to apply 40% and 20% Discount Just do it like this was 2000*0.6*0.8 = 960
Sometimes It's Also Asked
two successive discount of 30% and 40% is Equal to what Single Discount.
No need to worry Just do
the regular Stuff. If MP was 1 after 30% discount it will become 0.7
and after 40% it will be 0.6
So multiply the values.
0.7*0.6 = 0.42.
Now This 0.42 is The Final
SP
So total Discount will be
equal to 1- 0.42 = 0.58 or 58%
Lets see 1 more example.
What will the Single
Equivalent discount for two Successive Discount of 40% and 50%?
Let MP = 1
Now apply discount 0.6*0.5 =
0.3 = SP
So Discount = 1- 0.3 = 0.7
or 70%.
Case-15: Equation Based
Question,
it's not a single case
many Question can be Made From This case But basic idea is you have to make a
mathematical Equation To Solve Such type of Questions.
A trader gets a profit of
25% on an article. If he buys the article at 10% lesser price and sells it for
Rs. 2 less, he still gets 25% profit. Find the actual CP of the article.
Let Assume the CP of the
article was x. So according to Question The SP must have been 1.25x
Now He buys the article at
10% lesser price that means he buys it at 0.9x
And he sells it 2rs less
which means at 1.25x - 2
He will still get 25% profit
But This 25% will be calculated on 0.9x because it's the new CP
So 1.25x - 2 - 0.9x = 25% of
0.9x
0.35x -2 = 0.225x
0.35x - 0.225x = 2
0.125x = 2
x = 2/0.125 = 2000/125 = 16
So CP = 16.
Another One
A trader Sells an Article at
25% profit If he had Sold the item at 10 Rs. more the profit would have been
30%. Find The CP?
It's very simple question In
this type of question just assume CP as x.
And Convert the % value of
Profit into decimal and Then Solve the question Accordingly.
25% of x = 0.25x
and 30% of x= 0.3x
Now in the Question it is
said The dealer would get 10rs more if the profit is 30% Or the difference
between 25% profit and 30% profit is 10Rs
So 0.3x - 0.25x = 10
0.05x = 10
x = 10/0.05 = 1000/5 = 200
One More Question, A dealer
Sells an Article at 20% profit If he had sold the article at 500rs less he
would have suffered a loss of 30%. Find CP
Just Take CP as x
so 20% profit will be = 0.2x
30% loss = -0.3x[ remember
loss is assigned as negative]
So according to Question the
Difference between 20% profit and 30% loss is 500rs
So 0.2x - ( -0.3x) = 500
0.2x + 0.3x = 500
0.5x = 500
x = 500/0.5 = 5000/5 = 1000
Quiz :
Time: (5-6) minutes:
1. Aadesh bought a combined
total of 25 monitors and printers. He marked up the monitors by 20% on CP while
each printer was marked up by Rs. 2000. He was able to sell 75% of the monitors
and 2 printers and make a profit of Rs. 49,000. The remaining monitors and 3
printers could not be sold by him. Find his overall profit or loss if he gets
no return on unsold items and it is known that a printer costs 50% of a
monitor.
(a) Loss of Rs. 48,500
(b) Loss of Rs. 21,000
(c) Loss of Rs. 41,000
(d) Data Inadequate
(e) None of these
2. A rickshaw dealer buys 30
rickshaws for Rs.4725. Of these, 8 are four seaters and rest are two seaters.
At what price must he sell the four seaters so that if he sells the two seaters
at 3/4th of this price, he makes a profit of 40% on his outlay.
(a) Rs. 180
(b) Rs. 270
(c) Rs. 360
(d) Rs. 450
(e) None of these
3. Ritesh bought 25 washing
machines and microwave ovens for Rs. 2,05,000. He sold 80% of the washing
machines and 12 microwaves ovens for a profit of Rs 40,000. Each washing
machine was marked up by 20% over cost and each microwave oven was sold at a profit
of Rs. 2,000. The remaining washing machines and 3 microwave ovens could not be
sold. What is Raghav’s overall profit/loss?
(a) Rs. 1000 profit
(b) Rs. 2500 loss
(c) Rs. 1000 loss
(d) Cannot be determined
(e) None of these.
4. A flat and a piece of land
were bought by two friends Tarun and Varun respectively at prices of Rs. 2Lakh
and Rs. 2.2 Lakh. The price of the flat rises by 20% every year and that of
land by 10% every year. After two years, they decided to exchange their
possessions. What is approx. percentage gain of the gainer?
(a) 7.56%
(b) 6.36%
(c) 4.39%
(d) 3.36%
(e) None of these
5. Sunil calculates his
profit percentage on the selling price whereas Sujeet calculates his profit on
the cost price. They find that the difference of their profits is Rs. 900. If
the selling price of both of them are the same, and Sunil gets 50% profit and
Sujeet gets 40% profit, then find their selling price.
(a) Rs 4200
(b) Rs 4500
(c) Rs 4000
(d) Rs 4800
(e) None of these
6. A reduction of 10% in the
price of salt enables a person to buy 2 kg more for Rs.180. Find the reduced
and the original price per kg of salt respectively.
(a) Rs 10, Rs 9
(b) Rs 9, Rs 10
(c) Rs 18, Rs 20
(d) Rs 20, Rs 18
(e) Rs 18, Rs 16.2
7. A person sold his watch
for Rs. 24. If the percentage of his loss was equal to the cost price , then
the watch would have cost him
(a) Rs. 40
(b) Rs. 60
(c) Rs. 50
(d) Rs. 80
(e) None of these
8. A man buys two horses for
Rs. 1550. He sells one so as to lose 23% and other so as to gain 27%. On the
whole transaction he neither gains nor loses. What does each horse costs?
(a) 807,743
(b) 817,733
(c) 827,723
(d) 837,713
(e) None of these
9. An orange vendor makes a
profit of 20% by selling oranges at a certain price. If he charges Rs. 1.2
higher per orange he would gain 40%. Find the original price at which he sold
an orange.
(a) Rs. 3
(b) Rs. 12
(c) Rs. 4.8
(d) Rs. 6.0
(e) None of these
10. After selling a watch,
shyam found that he had made a loss of 10%. He also found that had he sold it
for Rs.27 more, he would have made a profit of 5%. the actual initial loss was
what percentage of the profit earned,had he sold the watch for a 5% profit?
(a) 23%
(b) 150%
(c) 200%
(d) 180%
(e) None of these.
Answers &
Explanation;
1. a 2. b 3.
c 4. e (8.189 approx. ) 5. a 6. b 7. e (Either Rs 40
or Rs 60) 8. d 9. e (Rs. 3.60) 10. c
Explanation:
1.Total Number of printers =
5 (2 sold , 3 unsold) Monitors = 20. Profit made on Printers sold =
2000*2 = 4000. Monitors sold = 20*75% = 15 Profit made on Monitors
sold = 49000-4000 = Rs.45000. Profit made per monitor = 45000/15 =
3000. 20% of CP of Monitor = 3000 CP of Monitor = 15000. CP of
Printer = 7500 Total CP = 15000*20 + 7500*5 = 3,37,500 Total SP =
18000*15 + 9500*2 = 2,89,000 Loss = 48,500
2. Total investement = Rs.
4725 Total SP = 1.4*4725 = 6615 Now, Let the price of 4 seater be x
then price of two seater will be .75x. 8x + 22*0.75x = 6615 24.5x=
6615 or x = 270
3. Total number of
Microwave ovens = 15 (12 sold +3 unsold) Hence, Washing machines =
10 He sold 12 ovens and 8 washing machines Hence, In total he sold
80% of both Thus, He sells 80% of both at a profit of Rs.
40,000. Cost of 80% of the goods = 0.8*2,05,000 = 1,64,000 Hence,
Total SP = 1,64,000+40,000 = 2,04,000 CP = 2,05,000 Loss = Rs.1000
4. After 2 years
:- Flat would be worth = 2Lakh* 1.2*1.2 = Rs. 288000 Land would be
worth= 2.2Lakh*1.1*1.1 = Rs. 266200 Profit of the Gainer = Rs.
21800 Profit % of the gainer = 21800*100/266200= 8.189(approx) Also
if loss% woudd have been asked of the loser loss% = 21800*100/288000 =
7.56 (approx. )
5. Let SP be Rs. 100 CP
for Sunil = => (SP-CP)*100/SP = 50 CP for Sunil ==> (100-CP)*100/100
= 50 or CP = Rs. 50 (Divided by SP as Profit calculated on SP) Profit
for Sunil = 100-50 = Rs 50 Now, CP for Sujeet = (SP-CP)*100/CP =
40 (100-CP)*100= 40CP or CP for Sujeet= Rs. 1000/14 Profit for Sujeet
= 100-100/14 = 400/14 Now, Difference in profit when SP is 100 = 50-400/14
= 300/14. Now, Equating difference and SP, we have 300/14 : 100 : :
900 : SP SP = 900*100*14/300 = Rs. 4200
6 . Let originally he buy X
kg for Rs. 180 Now, he will buy X+2 kg for Rs. 180. Reduction in
original price =10% (180/X)/kg*90/100 = [180/(X+2)]/kg 90(X+2) =
100X X = 18 Therefore, Originally he bought 18kg. Original Price
= Rs. 10/kg Reduced Price = Rs. 9/kg
7. SP = Rs. 24 Let CP
be X hence, Loss% = X (X-SP)*100/X = X or (X-24)*100/X =
X X^2-100X+2400 = 0 (X-60)(X-40) = 0 X= 60 or 40
8. Let CP of one be X and
other be Y X+Y = 1550….(i) ATQ:- 0.77X + 1.27Y = 1550…(ii) (as
no profit and no loss is there) Solving both, we get 50Y = 35650 or Y
= 713 Hence, X = 1550-713 = 837 Therefore, CP of each horse = 837,713
9. Let the CP be Rs. x/
orange Profit = 20% SP = Rs. 1.20x Now, If case :- SP =x+
Rs.1.2 Profit = 40% Therefore, we can say 1.40x = x+1.2 or x =
Rs. 3 Hence, Original SP = Rs 1.2x = Rs. 3.60/-
10. Profit= 5% (If case
) 5% of CP ------> Rs. 27 So, CP = Rs. 540 Now, Loss% =
10 Loss =Rs. 54 Required % = 54*100/27 = 200%